In the snippet below:
#include <stdio.h>
void swap (int*, int*);
// ^----(1)
int main (void) {
int a = 21;
int b = 17;
swap(&a, &b);
printf("a = %d, b = %d\n", a, b);
return 0;
}
void swap (int *pa, int *pb) {
// ^----(2)
int t = *pa;
*pa = *pb;
*pb = t;
return;
}
Which of these between (1) and (2) can be considered as a function prototype?
I know shit all about c, but if I were to guess I would say 1. Because to be it is defining the signature of the function.
I am an idiot though and you should disregard what I say because I do not C.