Specifically chemistry stemlords A 10.00 g sample of an unknown water soluble barium salt is treated with an excess of Na2SO4 to precipitate 11.21 g BaSO4. Which barium salt is it?
A. BaCl2
B. Ba(O2CH)2
C. Ba(NO3)2
D. BaBr2
Help
Specifically chemistry stemlords A 10.00 g sample of an unknown water soluble barium salt is treated with an excess of Na2SO4 to precipitate 11.21 g BaSO4. Which barium salt is it?
A. BaCl2
B. Ba(O2CH)2
C. Ba(NO3)2
D. BaBr2
Help
Take the mass of precipitate produced and multiply it by the molar mass of BaSO4 (233.4 g/mol)to get the moles of precipitate. Then, divide the mass of the unknown by that amount of moles to find the molar mass and see which of the answers it corresponds to.
spoiler
11.21 g BaSO4 / 233.4 g/mol BaSO4 = 0.04804 mol BaSO4
10.00 g unknown / 0.04804 mol = 208.15 g/mol unknown
Going through the list we can see that this corresponds to the mass of barium chloride (BaCl2)