Venustum [they/them] to memes • 2 years agoSomeone check up on that teacherimagemessage-square39 fedilinkarrow-up192
arrow-up192imageSomeone check up on that teacherVenustum [they/them] to memes • 2 years agomessage-square39 Commentsfedilink
minus-squareElmLion [any]hexbear1·edit-22 years ago I never said this. What are you talking about? The gradient of any line is mx + c = y, that's grade school math. That's all you used to work it out and you're claiming you used calculus. Alas, the answer for the coveted star was: Multiply the equation with d/dt: (d/dt) * t*sqrt(26) = dt * sqrt(26) / dt. dts cancel out, therefore the derivative is sqrt(26). Still a very unnecessary (and simple) application of calculus, but at least it would've shown that's whatcha did. link
minus-squareBeamBrain [he/him]hexbear4·2 years agoI never used the slope equation. I took a derivative d/dt. I clearly indicated the step where I did that. At this point, I can only conclude that you're keeping this going out of some weird desire to get one over on me, so I'm gonna disengage. link
The gradient of any line is mx + c = y, that's grade school math. That's all you used to work it out and you're claiming you used calculus.
Alas, the answer for the coveted star was:
Multiply the equation with d/dt: (d/dt) * t*sqrt(26) = dt * sqrt(26) / dt.
dts cancel out, therefore the derivative is sqrt(26).
Still a very unnecessary (and simple) application of calculus, but at least it would've shown that's whatcha did.
I never used the slope equation. I took a derivative d/dt. I clearly indicated the step where I did that. At this point, I can only conclude that you're keeping this going out of some weird desire to get one over on me, so I'm gonna disengage.