I get it, it's projected on a comlplex sphere. B and C are the same point
Literally, this is one of those questions where they're testing logic and your understanding that the figures aren't necessarily representative of physical reality.
Maybe the problem is constructing a metric that makes this diagram true. Something like d(x,y) = | |x| - |y| | might work but I'm too lazy to check triangle inequality.
Wish me luck for I'm doing trig test with radians (2 pi rad = 360 ?)
Radians are the objectivly better way to do angles tho. Just remeber π=180deg and ur right. Btw here is a another brain fuck the units radians/second is just Hz
Thank you for reminding me!
Btw, Radians/sec = Hz? What is this, physics?
The easiest way to think about it is that 1 full rotation (2*pi radians) in 1 second makes 1 Hz.
The number of rotations made in a second corresponds to Hz in the same way that the number of sine wave periods that fit in a second also represents Hz. This gif does a really good job of showing how rotation relates to sine/cosine waves, which just so happens to help visualize the rad/s -> Hz <- periods/s relationship:
*removed externally hosted image*
Engineering unit maths. Cos angles are unitless so radians/second =1/second=Hz
funny Interpretation: in the complex plane, the imaginary axis is orthogonal to the real axis. so instead of the edge marked with i (AC), imagine an edge of length 1 orthogonal to that edge. It would be identical to AB, so
ACCB is 0.But then CB couldn't also be 0; wouldn't it be
cos(1 + i)? Or something like that.oh I mixed up the points, I meant to say CB is 0 in the end
