Isn't it still finding the rate of change with respect to time? You find the derivative of the function even if that result is a constant rate. That's differential calculus, no?
It has no relation to differential calculus, calculus relates to continuous change. Pythagoras could've worked this out about 2000 years prior to the discovery of calculus. You're not finding the gradient of an effectively infinitesimal point on an ever-changing curve.
Yes, this is an arithmetic, not a calculus problem.
I guess a little geometry
Rewriting this question to make it so they're accelerating at those speeds instead.
Isn't it still finding the rate of change with respect to time? You find the derivative of the function even if that result is a constant rate. That's differential calculus, no?
Maybe I'm wrong.
It has no relation to differential calculus, calculus relates to continuous change. Pythagoras could've worked this out about 2000 years prior to the discovery of calculus. You're not finding the gradient of an effectively infinitesimal point on an ever-changing curve.
Apologies, my math is dreadful.