Isn't it still finding the rate of change with respect to time? You find the derivative of the function even if that result is a constant rate. That's differential calculus, no?
It has no relation to differential calculus, calculus relates to continuous change. Pythagoras could've worked this out about 2000 years prior to the discovery of calculus. You're not finding the gradient of an effectively infinitesimal point on an ever-changing curve.
The question is asking for the rate at which they're moving from one another, so the answer will be a number in ft/sec. The problem probably wants you to set it up as related rates and then do integration.
lmao
also wouldn't the distance between them grow at a constant rate? am i an idiot? they're each moving at a constant speed in straight lines right?
Yes, this is an arithmetic, not a calculus problem.
I guess a little geometry
Rewriting this question to make it so they're accelerating at those speeds instead.
Isn't it still finding the rate of change with respect to time? You find the derivative of the function even if that result is a constant rate. That's differential calculus, no?
Maybe I'm wrong.
It has no relation to differential calculus, calculus relates to continuous change. Pythagoras could've worked this out about 2000 years prior to the discovery of calculus. You're not finding the gradient of an effectively infinitesimal point on an ever-changing curve.
Apologies, my math is dreadful.
The question is asking for the rate at which they're moving from one another, so the answer will be a number in ft/sec. The problem probably wants you to set it up as related rates and then do integration.
Also I haven't done calculus in like 6 years